Imagine that you have a line, a point (p1) belonging to that line and you need to find a 2nd point (p2), also belonging to the line, that's at a specific distance (d) from the 1st point.
We could try to find the circle that has p1 as the center and d as the radius and check where the circle intersects with the line. But I want to try a different method that uses the line's slope and trigonometry.
First we have to take into account the equation that define the slope (m) of a line:
If we take a closer look, and remember how the trigonometric functions are tied to finding the projections of a line, we see that the slope is in fact this:
This means we can use the other 2 trigonometric equations that define the projections from the line to find the coordinates of the 2nd point:
And to find how much the angle is we just need to used this:
We could try to find the circle that has p1 as the center and d as the radius and check where the circle intersects with the line. But I want to try a different method that uses the line's slope and trigonometry.
First we have to take into account the equation that define the slope (m) of a line:
m = y2 - y1
x2 - x1
x2 - x1
If we take a closer look, and remember how the trigonometric functions are tied to finding the projections of a line, we see that the slope is in fact this:
m = tan α
This means we can use the other 2 trigonometric equations that define the projections from the line to find the coordinates of the 2nd point:
sen α = y2 - y1 <=> y2 = d sen α + y1
d
d
cos α = x2 - x1 <=> x2 = d cos α + x1
d
d
And to find how much the angle is we just need to used this:
m = tan α <=> α = arctan (m)
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